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Why after calling the QuickSort function it doesn't show the sorted array
8 Réponses
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George Ryan
You mean you get output for original array and the sorted array? I can only see output of original array, but sorted array isn't showing.
I think problem lies in `QuickSort` function, if I comment the line that calls `QuickSort`, then code runs ok. Although obviously the array is intact in second output.
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Sigmentation fault it showing check your loops may be it going to be infinite times
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George Ryan
Polymorphism doesn't play here, I take it you meant the forward declaration of QuickSort function at line 7?
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George Ryan Ipang ♨️♨️ i found the error
The brackets[] in 57 line were not in the right place
It looked like this before : while(s_arr[right>middle]) ;
That's why it didn't work
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Good job zaya1235 👍
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I'm not sure what the problem is, all of the array items seem to print just fine
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Segmentation fault? That's odd it works just fine for me.
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Ipang Ah yeah, one of my guesses is it's a problem with polymorphism. They defined two different quick sorts, I'm not sure which one main is calling