include <stdio.h> int main() { unsigned int i; int count=0; for (i=0;i<10;i--) { count++; } printf("%d ",count); return

Question

What is output

Answer 1

Ankit Kumar

Condition execute hi nhi hoga to loop ke bahar automatic a jayega.

Answer 2

After sorting all the errors the answer will be 1

Answer 3

Ankit Kumar

i = 0 ke case ke increment hoga uske baad nahi hoga kyonki i-- ki vajah se next iteration ke liye i = -1 hoga and loop execute nahi hoga to count increase nahi hoga. Count 1 hi rahne wala hai.

Mujhe lagta hai itna kafi hai samjhane ke liye.

Answer 4

Remember one thing first the condition is checked then the body of the loop is executed (if condition holds true) then atlast after coming out of the body the the updation (increment or decrement) takes place

Answer 5

Loop is control statment, which repeats its execution if condition is true

So program will run for only for i=0, however i--, which is a decrement operator, and now i become -1 so condition didn't satisfy then loop stop execution and went to next statment(which is displaying count )

Answer 6

Nhi I ko unsigned declared kiya hai to vo negative value le hi nhi sakta to infinte loop nhi hoga .

Answer 7

It's unsigned int it will execute only once ite output is 1

Answer 8

Ya you are correct

Answer 9

Vo sab hata kar batyie

Answer 10

You have not closed the main function too.

Answer 11

How

Answer 12

Explain

Answer 13

Ankit Kumar

1 because after i = 0, i will be -1 because of i--

so next condition will not execute.

Answer 14

I=-1 uske bad kya hoga loop se bhar kase gayenge

Answer 15

Kya I negative value gain nhi karega or unsigned ka maximum value gain karega or loop se out ho gayega

Answer 16

At first it will check the condition and go inside the loop and atlast it will decrement the value

Answer 17

Cont to for loop ke andar hi hai to count increment kase hoga

Answer 18

Satik koi mujhe samjha sakta hai

Answer 19

Thanks

Answer 20

You have an endless loop. In your for loop, since you start with i=0 and decriment every time, i will always be less than 10