Can u find the bug ? Plz run the code in else statement leap year program plz.

Question

year = int(input())
if year%4!=0:
print("Not a leap year")
elif year%100!=0:
print("Not a Leap year")
elif year%400==0:
print("Leap year")
else:
print("Not a leap year")

Answer 1

Mohammad Saad not every year that gets divided by 4 is a leap year.

Answer 2

Mohammad Saad year 1700,1800 and 1900 aren't leap year but 4 divides each of them

Answer 3

Edited
year=int(input())
if(year%4==0 and year%100!=0 or year%400==0):
print(leap year")
else:
print("Not a leap year ")
https://code.sololearn.com/cLCzB08UTSQq/?ref=app

Answer 4

Abhay Bro can you explain how ?pls give some example

Answer 5

I dont know about it thanks bro

year=int(input())
if(year%4==0 and year%100!=0 or year%400==0):
print("leap year ")
else:
print("not a leap year ")
#Use this code