I wanna print factors of 2,3,5 only.

Question

N=7; output should be 8. Everytime it prints the factor it should get incremented. 1,2,3,4,5,6,8,9,10,12,14,15,16,18,20••••••

Answer 1

int n =12;
int i = 1;
int no=0;
for(i = 1 ; no < = n ; i++)
{
if(i%2==0 || i %3==0 || i %5==0)
no++;
}
printf("%d", i-1);

//This works i think.. Check it once..
But 1%2, 1%3, 1%5 not 0 so 1 not counted...

edit: Ajith use array to store factors and display values to easy understand what is missing... hope it helps..

Answer 2

a, f = int(input()), 0
for x in range(a):
f += sum([(x+1)%y==0 for y in [2,3,5]]) == 1
print(f)

""" Prints only the individual factors; no overlap """

Answer 3

int n =12;
int i = 1;
int no;
for(i = 1 ; i < = n ; i++)
{
if(i%2==0 || i %3==0 || i %5==0)
no++;
else
continue;
}
printf("%d",no);

Answer 4

N=12;output would be 15

Answer 5

For n=12, how the output is 15? Give some clarity...
2,3,4,5,6,8,9,10,12 => 9 only..

Answer 6

1,2,3,4,5,6,8,9,10,12,14,15
n[12] = 15;

Answer 7

for n == 12, your actual code give you 9:

loop goes from 1 to n (included), so 'no' max value would be n... not 'factors' list: 1, 7,11, so 12-3 = 9...

the list you gave is not the result of your code ^^ (wich require some corrections to be ran)