Why this happens only in java why it doesn't happen in c,python or cpp?

Question

Question:
I have made same codes in c,cpp,java and in python and all have different outputs??I have posted code see and tell me 🤔🤔
Java
System.out.println("2+2="+2+2);
Output:=>2+2=22
C
printf("2+2="+2+2);
Output:=>Error
Cpp
cout<<"2+2="+2+2;
Output:=>no output
Python:
print("2+2="+str(2+2))
Output:=>2+2=4
https://code.sololearn.com/c5V1j3KOMhe6/?ref=app
https://code.sololearn.com/c1pbSZr5TWr3/?ref=app
https://code.sololearn.com/c6XYEv73EF08/?ref=app
https://code.sololearn.com/c6g1iK5TQu2F/?ref=app
WHY THIS HAPPENS TELL ME WITH FULL EXPLANATION🤔🤔

Answer 1

🌟ᴀɴᴜʀᴀɢ[STUDY 📚]🌟

In Java when you add numbers with String then it becomes string. So here "2+2=" + 2 + 2 will be 2+2=22 but if you add numbers within parenthesis then it add numbers. For example System.out.println("2+2="+(2+2)); In this case result will be 2+2=4

Answer 2

in C/C++, "string" + n . n being a number, is just a pointer arithmetic.
you get no output because 2+2 exceeds the length of "2+2="
to understand better change 2+2 to a smaller number.
example:
cout << "2+2=" + 1 ;
outputs: +2=
it's like saying print the characters from str[1] to the end.
to do string concatenation in c/c++ convert the int into a string.

Answer 3

JAVA
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When you add an integer to a string, a new String object is created using in the SCP (String Constant Pool). Since the resultant object is a string, there is no error. This is generally discouraged as the creation of a new string object is costly (memory wise)

Unfortunately, I'm not sure about the case in C or Cpp

Answer 4

Bahha🐧 Thanks for the awesome explanation!

Answer 5

Thanks ♨ Soumik 🎶 I Am AJ ! For better explanation I can't understand because I come from python,html,css and js so I couldn't understand it comes in community challenge so I ask