Safety deposit boxes

Question

boxes=input().split(",")
key=input()
time=0
listlen = len(boxes)
for i in range(0,listlen):
if boxes[i]!=key:
time += 5
else:
time += 5
return time
print(time)

When i run this code, 'return outisde function' pops up. I dont know what part is wrong....

Answer 1

#my solution

sth=input().split(',')
target=input()
print((sth.index(target)+1)*5)

Answer 2

Here is a possible solution.

BoxContent = input().split(',')
item=input()
time=1
for n in BoxContent:
if item==n:
break
else:
time+=1
time=time*5
print(time)

Answer 3

all=input().split(",")
t=input()
print((all.index(t) + 1)*5)

Answer 4

you are incrementing time, not returning it from inside a function.

delete the "return time" line and the code will run

Answer 5

Thanks Slick. Then how to terminate the for loop when else statement is fulfilled and get the time value. I want the for loop keep running in if statement before else statement runs.

Answer 6

The if-else statement should be a "one or the other" situation. I'm assuming "key" is the final input (or just the value at which you want) to stop the time. is this correct?

Answer 7

Yes it is.

Answer 8

Okay cool, then use a break statement after you add 5 to time to jump out of the for loop.

it should read: if the value of boxes[i] isn't equal to the value of "key", add 5 to time. If not, add 5 to time and break out of the loop.

Im not 100% sure of the purpose of your program so this is how i guess it should go.

Answer 9

I think it'll work

boxes=input().split(",")
key=input()
time=0
listlen = len(boxes)
for i in range(0,listlen):
if boxes[i]!=key:
time += 5
else:
time += 5
break
print(time)

Answer 10

Try with enumerate (<iterable>, <start>). The enumerate function is very useful here. It returns some separated tuples with an index number and a list value in each separately like >> (0, item1), (1, item2) etc.

Answer 11

My solution is:

i = input().split(",")
x = input()
c = 0

for t in i:
if not t == x:
c += 5
else:
c += 5
break

print(c)

But with what MING ZI CHEN wrote, I changed it to:

print((i.index(x)+1)*5)

And that is way better 😊🙌

Answer 12

My solution:

boxes = input().split(",")
item = input()
x = boxes.index(item)
wait = (x+1)*5
print(wait)

Answer 13

This is my solution using c++

#include <iostream>
#include <string>
#include <sstream>
#include <vector>
using namespace std;

int main() {
string items_string;
getline(cin, items_string);

string target_item;
getline(cin, target_item);

// Parse the items string into a vector of strings
vector <string> items;
stringstream items_stream(items_string);
string item;
while (getline(items_stream, item, ',')) {
items.push_back(item);
}

// Find the target item in the vector
int time = 0;
for (const string& item : items) {
time += 5;
if (item == target_item) {
break;
}
}

cout << time << endl;

return 0;
}

Answer 14

boxes = input('boxes>: ').split(',')
item = input('item>: ')
time = 5

for i in boxes:
if i == item:
print(time)
else: time+=5

Answer 15

n=input()
y=input()
x=n.split(',')
print(x)
for i in x:
if i==y:
print((x.index(i)+1)*5)

Answer 16

x=input()
SarK=input()
x=x.split(',')
print(5*(x.index(SarK,0,len(x)-1)+1))
The only problem is case#4

Answer 17

items = input().split(",")
item = input()

time=0
for i in items:
time += 5
if i == item:
break

print(time)

Answer 18

This is my solution:

s=input().split(",")
r=input()
count=0
for i in s:
iter(s)
count+=5
if i==r:
print (count)