How do u calculate average mark for a maximum of 5 entries using a dictionary

Question

student={}
for i in range(5):
name=input()
mark=int(input)
student.update({'name':name,'mark':mark})
print(student)

Answer 1

well you loop over the dictionary keys, add the marks value and divide it by 5.
i. e.
sum=0
for i in student:
sum+=student[i]
print(sum/5)

And it is "mark=int(input())"

Answer 2

simbarashe
Is this 5 students with 1 mark each? Which is what the code you have posted does. If so you can just use the sum() function on a list of the values from the dict, divided by the length of the dictionary.

average_mark = sum(list(student.values())) / len(student)

If this is not the correct structure for your dictionary then please describe further.

Answer 3

Would something like this help

students = {
"Bob" : 41,
"Jak" : 62,
"Amy" : 98,
}

total = 0

for i in students:
total += students[i]

average = total / len(students)
print(average)

Answer 4

Abhay i have done wat u suggested but still not working

Answer 5

simbarashe can you show me your code?

Answer 6

student_1 = input()
...
student_5 = input()

sum = student_1 + ... + student_5

avg = sum/5

print(avg)

You can attribute a number for each student. Python also understand Ab>Ac = True. You can put them in order too.