Can anyone tell me. How to solve this question.

Question

You’re making a calculator that should add multiple numbers taken from input and output the result.

The number of inputs is variable and should stop when the user enters "stop".

Sample Input
4
32
6
stop

Sample Output
42

Use an infinite loop to take user input and break it, if the input equals to "stop".

Answer 1

First of all in line 4 you have to check variable x so in place of input type x. Second, remove line 5 because you don't have to print stop according to question you have to print only sum.
Here's the code, Hope you understood!!

sum = 0
while True:
x = input()
if x == "stop":
break
else:
sum += int(x)
print(sum)

Answer 2

Please the community want to see your code before.Then we will try to help😉
Thanks for understanding

Answer 3

The question is in description

Answer 4

I mean show us your try

Answer 5

This code should work:

total = 0
while (True):
num = input("Enter a number: ")
if (num == "stop"):
break
total += num
print(num)

:)

Answer 6

Navraj, in your code, the problem is that your code should not print "stop" when it is inputted. That is all of the problem.

Answer 7

Navraj

Code has bug

if input == "stop":

Needs to be replaced it with following

if x == "stop":

DHANANJAY

Answer 8

sum = 0
while True:
x = input()

if x != 'stop':
sum += int(x)

else :
break

print(sum)

Answer 9

Can you tell me what's wrong in this code??
sum = 0
while True:
x = input()
if input == "stop":
print("stop")
break
else:
sum +=int(x)
print(sum)

Answer 10

sum = 0
while True:
x = input()
#your code goes here

if x=='stop':
break
else:
sum=sum+int(x)
print(sum)

Answer 11

another one
sum = 0
while True:
x = input()
#your code goes here
if x != "stop":
sum = sum + int(x)
else:
break
print (sum)

Answer 12

Here's my code:

sum = 0

while True:
x = input()
if x != 'stop':
sum += int(x)
if x == 'stop':
break

print(sum)

Answer 13

Why my code does not work?
sum = 0
while True:
x = input()
#your code goes here
x += 1
if x == "stop":
break
else:
sum += int(x)
print(sum)

Answer 14

Sorry but I do not understand a word you have written?

Answer 15

Please, Am I tolerable or not ?

DHANANJAY PATEL

Answer 16

Can anyone help me? I have asked you guys two days ago.. I am frustrated because can't move forward and honestly I have no idea what is wrong with my code and what I am doing wrong....

Answer 17

Try this one and you'll get results

sum=0
while True:
x = input()
#your code goes here
if x != "stop":
sum = sum + int(x)
# print(sum)
else:
break
print(sum)

Answer 18

100% correct
sum = 0
while True:
x = input()
#your code goes here
if x == "stop":
break
sum = sum + int(x)
print(sum)

Answer 19

Type in the code that allows for entering a number
and storing it in the variable a:
>> a;

Answer 20

Fill in the blanks to create a loop that outputs all the numbers from 1 to 100 except the number 42