I've written code for Balanced Parenthesis, all work but Case 7. I can't see my error and would appreciate help.

Question

def balanced(expression):
#your code goes here
stack=[]
count = expression.count(")")
for i in expression:
stack.insert(0,i)
if i == "(":
stack.pop()
count-=1
if count > 0 or count < 0:
return False
else:
return True

print(balanced(input()))

Answer 1

If input is " ) ( " , output ? Should be false

Answer 2

I Am AJ ! Not sure what you meant but you did help in reminding me the definition of the question. I should've just added parenthesis to the stack and not each char. It's solved now, thanks for trying.

Answer 3

Yeah I just thought of that, trying to figure out how to fix it though...

Answer 4

"""here is my code but my test case 7 is failing i guess its because i am not being able to handle for empty stack but when i fulfill that criteria many test cases arise as well """

open_parenthesis = ['(','{','[']
close_parenthesis = [')','}',']']
stack = []

def balanced(expression): #--->(x+)*(z-2*(6))
#your code goes here
o = 0
c = 0
for p in expression:
if p in open_parenthesis:
o += 1
elif p in close_parenthesis:
c += 1

if o == c:
return True
else:
return False

print(balanced(input()))

Answer 5

Olivia

You have to push ( in stack and on the basis of ( check if closing bracket ) match then remove ( from stack.

You can try this

https://code.sololearn.com/cmWTdRiciMhG/?ref=app