Why does the array have an ending / 0, but the stringing is not necessary?C langauge

Question

Why does the array have an ending / 0, but the stringing is not necessary?

Answer 1

STOP
The first one is an array of `int`.

The second one is an array of `char`. In C language, a string is an array of `char` with a null char '\0' as the string terminator (last character element in array).

The string terminator is used to signify the end of a string. Without the '\0' as the last char, computer will keep on printing the data in memory (casted as `char`) into the screen when we print the string, until a null char was located (somewhere far off).

`char` array only needs to have a string terminator '\0' when it is to be treated as a string.

Answer 2

You accidentally posted 2 copies of this thread. Please remove either one to help community reduce duplicate questions 👍

Answer 3

Ipang thank you, check DM please

Answer 4

Ipang int a[5]={1,2,3,4,5};
char b[5]=[a,b,c,d,'/0'];

like this

Answer 5

Ipang Is the strings aray, but the last one is 0 / and expresses the characters?

Answer 6

STOP
No problem 👌
But I have problem using DM, can't reply, only read