How can I solve FizzBuzz problem?

Question

I don't understand how will I solve this?

Answer 1

Chinmoy Roy

Use search option to get solution

https://www.sololearn.com/discuss/2548320/?ref=app
https://www.sololearn.com/discuss/2666911/?ref=app
https://www.sololearn.com/discuss/2676817/?ref=app

Answer 2

the last section says you need to skip even numbers.

add another if statement.

if x % 2 == 0: # how to test for an even number
...
...

Answer 3

as Slick suggested, I will only add

if x % 2 == 0:
continue # to pass even nums

# try to put this condition in the correct place

Answer 4

Hi! Please, show us your attempt. You have a code?

Answer 5

Post your code so we can help. If you haven't written any yet, i suggest you go back over the previous lesson

Answer 6

n = int(input())

for x in range(1, n):
if x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

# I can't solve it yet.
#The question is:

The given code solves the FizzBuzz problem and uses the words "Solo" and "Learn" instead of "Fizz" and "Buzz".
It takes an input n and outputs the numbers from 1 to n.
For each multiple of 3, print "Solo" instead of the number.
For each multiple of 5, prints "Learn" instead of the number.
For numbers which are multiples of both 3 and 5, output "SoloLearn".

You need to change the code to skip the even numbers, so that the logic only applies to odd numbers in the range.

# so help me there.

Answer 7

Agregar en el primer elif lo siguiente:

elfi x % 2 == 0:
print("")

no hay necesidad de imprimir el número, solo que sea la primera iteración y que omita el número par.

Answer 8

You need to follow the suggestions already given to you...twice.

In the correct place add:

elif x % 2 == 0:
continue