Why capture clause = working to update value in lambda

Question

Hi

Refer below code:
https://code.sololearn.com/cA4a45A25A18/#cpp

As = is non modifiable capture, why lambda function is able to modify value of member variable? Should it not be & instead of =?

Answer 1

From cppreference.com:

The current object (*this) can be implicitly captured if either capture default is present. If implicitly captured, it is always captured by reference, even if the capture default is =.

https://en.cppreference.com/w/cpp/language/lambda

Since the current object is captured by reference, you can modify it. However, as of C++20, the implicit capture of this via = has been deprecated, but it still works. Now you might want to capture [=, this] instead to be more explicit.

Answer 2

I have also work using lambda. I was working on a project called custom tshirts. Here is the URL of it: https://www.customtshirts.ae/tshirt-embroidery. I face many problems in the beginning as I was totally new in it. But thanks to my friend who helpmed a lot in this.

Answer 3

I am pretty much aware of this error myself. Back in 2019 when I was working on my client's project called Woven Labels Maker in Canada, I faced this problem a lot of times. Here is the link to that project https://www.wovenlabels.ca/ and as you can see it's working totally fine now. Thanks to this forum I would say that I was able to find the answer to this problem.

Answer 4

Using [=] in a lambda captures this by value, allowing modification of member variables. For non-member variables, [=] only captures copies, so they remain unmodified.
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Answer 5

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Answer 6

The capture clause in C++ lambda expressions allows variables to be accessed and modified within the lambda’s scope. Using `=` enables value capture, ensuring updates within the lambda. This approach is essential for functional programming. For expert storytelling, explore **fiction ghostwriting services in US** to bring creative ideas to life.
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Answer 7

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Answer 8

The capture clause in a lambda allows access to external variables. When using "=", it captures by value, creating a copy. However, if the captured variable is mutable (like using mutable), you can update it inside the lambda. For students needing clarity on such concepts, English Assignment Help can simplify technical writing and explanations.
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Answer 9

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