Trying to solve contacts database in python core

Question

We need to create a number formatting system for a contacts database.
Create a program that will take the phone number as input, and if the number starts with "00", replace them with "+".
The number should be printed after formatting.

Sample Input
0014860098

Sample Output
[phone]

My replaces 00 with + even in the middle which is not meant to be
import re
number=input()
str=number
pattern="00"
newstr=re.sub(pattern,"+",str)
print(newstr)
#your code goes here

Answer 1

#This amendment in your original code worked for me:

import re
inp=str(input())
pattern=r"00"
mat=re.search(pattern,inp)
if mat and mat.start()==0: # <-- change is here!
print(re.sub(pattern,'+',inp,1))
else:
print(int(inp))

""""Sample Input
0014860098

Sample Output
[phone]"""

Answer 2

import re

#your code goes here

number = input()
pattern = r"00"

if re.match(pattern, number):
print(re.sub(pattern, "+", number))
else:
print(number)

Answer 3

what is the essence of putting the sign "^" before the 00
as in r"^00"

Answer 4

Show your attempt bro

Answer 5

I used match and then treated the phone number string as a list and just sliced off the first two characters. To slice off the zeros,use entry[2:]. This leaves a string without the “00” at the beginning. Then add a “+” to the beginning of the string. This can be done in one line

import re
#your code goes here
entry = input()
if re.match("00",entry):
entry = "+" + entry[2:]
print(entry)

Answer 6

import re

#your code goes here
input_str = input()
pattern = r'^[0]{2}'

res = re.sub(pattern, '+', input_str)

print(res)

Answer 7

I came up with this and it seems to pass all tests:

import re

num = str(input())
pattern = r"00"

if num[:2] == "00":
newNum = num.replace(num[:2], "+")
print(newNum)
else:
num[:2] != "00"
print(num)

Answer 8

import re
number=input()
str=number
pattern="00"
newstr=re.sub(pattern,"+",str)
print(newstr)
#your code goes here

Answer 9

Thanks

Answer 10

number = input()
pattern = r"00"

if re.match(pattern, number):
print(re.sub(pattern, "+", number))
else:
print(number)

Answer 11

Hi, the following is my solution:-

import re

Number=input("phone number: ")

pattern = r"00"

if re.match(pattern,Number):
NewNumber = re.sub(pattern, "+", Number,1)
print(NewNumber)
else:
print(Number)

Answer 12

#My solution is here. I wish help you..

import re

phone_n = input("please enter your phone number: ")

patt = r"00"

match = re.search(patt, phone_n)

if match:
if match.start() == 0 and match.end() == 2:
phone_n = re.sub(patt, "+", phone_n, count =1)

print(phone_n)

Answer 13

#This worked for me only in sololearn. But when run outsite here, error occurs in line 2.

import re
num=input()
pattern=r"00"
num2=re.search(pattern,num)
if num2 and num2.start()==0:
print(re.sub(pattern,'+',num,1))
else:
print(num)

Answer 14

import re
str = input()
pattern = r"00"
num1= re.sub(pattern, "+" ,str)
num2 = re.search(pattern,str)
if num2 and num2.start() == 0:
print(num1)
else:
print(int(str))

Answer 15

import re
number=input()
pattern=r"^00"
newstr=re.sub(pattern,"+",number)
print(newstr)
#your code goes here

Answer 16

import re
num = input()
num=re.sub(r"^00","+",num)
print(num)
#your code goes here

Answer 17

import re

#your code goes here

phone_number = input()

pattern = "00"
replace = "+"

if re.match(pattern, phone_number):
print(re.sub(pattern,replace,phone_number,1))
else:
print(phone_number)