array in array

Question

Hey guys
i want to write a program to print 3 array in an array with use array of pointers
#include <stdio.h>
int main()
{
int arr1[3];
int arr2[5];
int arr3[2];
int *ARR[3]={arr1,arr2,arr3};
for(int i=0;i<3;i++)
{
scanf("%d",&arr1[i]);
}
printf("=============\n");
for(int i=0;i<5;i++)
{
scanf("%d",&arr2[i]);
}
printf("=============\n");
for(int i=0;i<2;i++)
{
scanf("%d",&arr3[i]);
}
printf("=============\n");
for(int i=0;i<3;i++)
{
for(int j=0;j<(i don't know what should i write heir);j++)
{
printf("%d ",ARR[i][j]);
}
printf("\n");
}
return 0;
}

Answer 1

One feasible way would be to use another array to contain info about each array's length, and make <j> loop run on those limits.

for (int i = 0, index[3] = { 3, 5, 2 }; i < 3; i++)
{
for (int j = 0; j < index[i]; j++)
{
printf("%d ", ARR[i][j]);
}
printf("\n");
}

Answer 2

Ipang
Thanks a lot