I expected 'return x' to be 1 but None was returned. Why??

Question

def fuc(x):
if x==1:
return x
else:
x-=1
fuc(x)
x=2
print(fuc(x),x)

Answer 1

On line 6, you just call fuc(x), you need to return the result as well by doing return fuc(x).

Answer 2

Good question and your expectation is acceptable.
Recursion needs a return. And it is a bit complicated to explain why.