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Can anyone find out why this code outputting a garbage value instead of sum of even numbers in the list?
#include <stdio.h> int main() { int sum=0,N,a[20]; printf ("enter the no.of elements"); scanf("%d",&N); for(int k=0;k<N;k++){ scanf("%d",&a);} for(int i=1;i<N;i++) { if(a[i]%2==0) sum=sum+a[i]; } printf("sum of even numbers =%d",sum); return 0; }
8 Réponses
0
Yeah I find it in second loop you run from 1 it should be from 0
+ 2
Thx for your response however i don't think so!
Cuz in scanf I had to mention array variable NAME where I wanna store my elements and here below a[i]
I indicates index of array elements everytime the for loop iterates!
+ 2
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I did but it's not giving right answer!
May be another bug is there?YUGRAJ
+ 1
I think you forget a[i] in scanf
+ 1
Ya thank you so much for your help😊YUGRAJ
0
Sorry you have to write there
scanf("%d", &a[k]) ;
Try this
0
#include <stdio.h>
int main() {
int sum=0,N,a[20],k,i;
printf ("enter the no.of elements");
scanf("%d",&N);
for(k=0;k<N;k++){
printf("le %d number is",k+1);
scanf("%d",&a[k]);
}
for(i=0;i<N;i++)
{
if(a[i]%2==0) sum=sum+a[i];
}
printf("sum of even numbers =%d",sum);
return 0;
}