98.2 help!

Question

So this is the question im stuck with and i cant seem to figure it out even though i have added a valueerror to the code but it still doesn't work. Can someone help explain why

To order a restaurant dish online, the user should enter the code of desired dish, which contains only digits. Write a program that will take the code as input, and output "Enter only digits" if it contains non-digit symbols, and output "Order accepted" if it doesn't.
If the ordering process went well, the program also should output "Bon appetit".

Sample Input
1437

Sample Output
Order accepted
Bon appetit

This is the code that i have created:
code = int(input())
#your code goes here
try:
print("Order accepted")
except ValueError:
print("Enter only digits")

else:
print("Bon appetit")

This was the original code:
code = input()

#your code goes here
try:

except

else

Answer 1

code = input()

try:
if code.isdigit():
print("Order accepted")
else:
raise ValueError
except ValueError:
print("Enter only digits")

else:
print("Bon appetit")

You didn't add the main logic to your code.. The if-else in try is important to solve the problem.

Answer 2

Hey there,
A bit late but liked to share my code! :)

code = input()

#your code goes here
try:
code == int(code)
print("Order accepted")
except ValueError:
print("Enter only digits")
else:
print("Bon appetit")

Answer 3

Zhi Hong

You can also take input in try block to handle error

try:
code = input()
dish = int(code)
print ("Order accepted")
print ("Bon appetit")
except:
print ("Enter only digits")

Answer 4

You can also try this way(don't forget to type "import re" at the top):

import re
code = input()

#your code goes here
pattern = r"\A[0-9]+\Z"
try:
if re.match(pattern, code):
print("Order accepted")
else:
raise ValueError

except ValueError:
print("Enter only digits")

else:
print("Bon appetit")