How can I check if a user inputs a char instead of an int?

Question

if the user inputs a char, the program will ask for an input again

Answer 1

BY KEEPING AN EYE ON HIM [LOL]

Answer 2

Scanner n = new Scanner (System.in);
System.out.print("...");
try{
sp = n.nextInt();
} catch(Exception e){
//Display your message here
}
if ( sp != 1 ) {
if ( sp == 2 ) {
System.out.println("...");
}
} else
System.out.println("...");

Answer 3

A suggestion:

you should find your question in google first because you will find various answers there.

//

https://stackoverflow.com/questions/21888309/check-for-character-instead-of-integer

https://stackoverflow.com/questions/38277715/how-to-check-if-user-input-is-a-certain-character/38283211

https://www.tutorialspoint.com/how-to-check-if-a-given-character-is-a-number-letter-in-java

Answer 4

If you want to keep asking the user to input values until it's an integer -

https://code.sololearn.com/cEMHpsL4XRBy/?ref=app

Answer 5

Azalea java.util.Scanner and java.util.InputMismatchException classes.

Answer 6

Soumik [Busy] what certain package do i need to import?😅

Answer 7

🅰🅹 🅐🅝🅐🅝🅣 thanks!!

Answer 8

import java.util.Scanner;

public class Main
{
public static void main(String[] args)
{
Scanner s = new Scanner(System.in);

while(true)
{

try{
int input = s.nextInt();
break;
}
catch(Exception e){
continue;

}

}
}
}

Here i'm looping until the input be an integer
It is possible because Java gives an error when you try to pass a char input to a int value whitout casting it

Answer 9

Soumik [Busy] what is the " ex" for in catch(InputMismatchException ex)?

Answer 10

Azalea

ex is an object of InputMismatchException . It can be anything like a, b, c, e