String ends with?

Question

Complete the solution so that it returns true if the first argument(string) passed in ends with the 2nd argument (also a string).

Examples:

solution('abc', 'bc') # returns true
solution('abc', 'd') # returns false

Please help I don't really know what's the problem and how to improve my code. If possible help!

Here is my code:

def solution(string, ending):
count = len(string)
if string[count] in ending:
return True
else:
return False

Answer 1

Okay how about
return string.endswith(ending)

Answer 2

How about this?

https://code.sololearn.com/ciDtlMnCyJvt/?ref=app

Answer 3

Let's debug
Count =3
String[3]=crashhhhhh index error

Please explain in own words how u want to solve it
Then we do it step by step

Answer 4

on line 3 I want to be able to count the end of the string and see if it is in the ending

Answer 5

My solution before was :

def solution(string, ending):
if ending in string:
return True
else:
return False

Answer 6

How can one count the end of a string?

Answer 7

so you see. if we count the length of the string its index is the last letter!

Answer 8

Example I dont really understand

Answer 9

https://code.sololearn.com/cj3pLwq6MGTl/?ref=app

Answer 10

Same as Frogged

example:

"sololearn"

str.endswith("rn") :true
str.endswith('n') :true
str.endswith('arn',0:start,8:end) :true