How do you solve Snell in the well problem, I have tried everything I need some guidance

Answer 1

Basswell Mbilima , Nwokoma Chimezirim

If you post your attempts, the community is more able to assist you.

We may be able to assist you with your misunderstanding.

Quite often, complete codes provided to others merely confuses them, & nothing is learnt.

But if you get assistance pertaining to your concept, then you have a better chance of understanding

Answer 2

Please post your attempt.

Answer 3

Rik Wittkopp this is my code .. test 1 n 3 are what's failing.... It's in JavaScript

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here

var distance = 0;
var day = 0;
do{
day++;
distance = distance + 5;
}while(distance < depth);

console.log(day);
}

Answer 4

Eashan Morajkar 👆

Answer 5

I finally solved it

We have to add 7 to the snail every day, then check if it has climbed out, if not we then minus 2. This is my code below

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var days = 0;
var h = 0;

for (h;h<=depth;) {
days++;
h += 7;
if (h >= depth) {
break;
}
h -= 2;
}

console.log(days);

Answer 6

Same here honestly, it is either I get case 1 correct and fail case 2, then when I change a particul variable, I get case 1 wrong and fail case 2

I hope the snail in a well challenge is the one from Javascript course?

Answer 7

function main() {
var depth = parseInt(readLine(), 10);
//your code goes here
var days = 0
var i = 0
while (i<depth){
i+=7
++days
if (i>=depth){break}
i-=2
}
console.log(days)
}