I'm unable to get the unique items in my dictionary please anyone help it......

Question

test_list={
'Rahul': {'Permanent Roomates': 2,
'Inside Edge': 3,
'Four More Shots Please': 3,
'Sacred Games': 3,
'Apharan': 2,
'Mirzapur': 3},
'Rishabh': {'Permanent Roomates': 3,
'Inside Edge': 3,
'Sacred Games': 5,
'Mirzapur': 3,
'Apharan': 3},

'Sonali': {'Permanent Roomates': 2,
'Inside Edge': 3,
'Sacred Games': 3,
'Mirzapur': 4},
'Ritvik': {'Inside Edge': 4,
'Apharan': 2,
'Sacred Games':4

},
'Harshita': {'Permanent Roomates': 4,
'Inside Edge': 4,
'Four More Shots Please': 2,
'Sacred Games': 3,
'Mirzapur': 3,
'Apharan': 2},
'Shubhi': {'Permanent Roomates': 3,
'Inside Edge': 4,
'Mirzapur': 3,
'Sacred Games': 5,
'Apharan': 3},
'Shaurya': {'Inside Edge':4,
'Apharan':1,
'Sacred Games':4}}

res = list(set(val for dic in test_list for val in dic.value()))
print("the unique value in list: " + str(res))

# Q - Extract

Answer 1

Akash Gupta

What about this?

setkey = set()

for id, info in test_list.items():
for key in info:
setkey.add(key)

print (setkey)

Answer 2

Which one is unique according to you?

Answer 3

Ipang as you seen in my dictionary there is 4 or 5 keys and those keys have some value which will same in different key so i want to print that value in my output. Sorry for bad English

Answer 4

"""
Akash Gupta as that's only the first part of your assignement, and the second part is to find comon series between two customers, I will rather build a new dict structure with series as keys, and storing list of customers as values:
"""

series = {}
for c, d in dataset.items():
for t in d:
if t in series: series[t].append(c)
else: series[t] = [c]

print("uniques series:")
print(*series.keys(), sep="\n")

# the 'series' dict will now help you to solve the second question ^^

Answer 5

Akash Gupta

Kaun sa value print karna hai?

Is it like this?

https://code.sololearn.com/cde6eYO63CIx/?ref=app

Answer 6

🅰🅹 🅐🅝🅐🅝🅣 ,visph thank you so much for giving your time.

Answer 7

🅰🅹 🅐🅝🅐🅝🅣 https://code.sololearn.com/cL1QvgQGxOqr/?ref=app

Check it here i think it's not working