Is "func" arg or keyword

Question

def apply_twice(func, arg):
return func(func(arg))

def add_five(x):
return x + 5

print(apply_twice(add_five, 10))

Is func a keyword or is it argument to execute add_five function???

Answer 1

'func' is an arbitrary argument name... so 'func' is an argument, not a builtin keyword...

arguments are special kind of variable used as placeholder to pass values (may be functions) to a function execution body...

Answer 2

Done ✅

Answer 3

nah, func is just a short placeholder name for an arbitruary function. It could be: 'pickles' the name really doesn't matter

Answer 4

Thanks to everyone, i got my ans ! Great help <3

Answer 5

I know the answer i just want to know that 'func' passed as a argument and the by python it treated as a function keyword?

Answer 6

But my question was totally different, no?😹😹 Anyway thank you so much for replying mate❤️

Answer 7

your question was to explain how the func function works, I gave you my explanations from which you could understand that there is no func keyword in Python, you can rename it to any other for example arg1

Answer 8

apply_twice(add_five, 10 ) =>
=> return add_five(add_five(10)) =>
=> add_five(10) # return 15
add_five(15) # return 20

func is an argument of the apply_twice function to which the add_five function is assigned with an argument x to which the add_five function is assigned with an argument value of 10

Answer 9

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