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Balanced Parenthesis // python data-structures
def balanced(l): s=[] for i in l: if i == "(": s.insert(0,i) elif i ==")": if s==[] : return False s.pop(0) return s==[] print(balanced(input())) ---------------------------------------- def balanced(l): if l.find('(') > l.find(')') : return False s = [] for i in l : if i == '(' : s.insert(0, i) elif i == ')' : s.pop(0) return s==[] print(balanced(input())) Why this two codes are not gave same results for test case #7 ???
1 Réponse
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Hirani Pranav ,
the second code crashes if input is e.g.: (()(()))))
▪︎the first code checks for an empty list with:
if s==[] : return False
▪︎the second code is not doing this check and ends up with an exception: < IndexError: pop from empty list >