Anybody tells how to solve type error?

Question

import java.util.Scanner;
public class converter{

toBinary(){
int x = 0;
return 0;
}
toBinary(int x){
String binary ="";
while(i>0){
binary = (i%2)+ binary;
i /=2;
}

}
}
//your code goes here

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.print(Converter.toBinary(x));
}
}

Answer 1

Amala Yakin try this code i edit it

import java.util.Scanner;
public class converter{

public static void toBinary(){
int x = 0;
}
public static String toBinary (int x){
String binary ="";
while(x>0){
binary = x%2 + binary;
x /=2;
}
return binary;
}
}
//your code goes here

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.print(converter.toBinary(x));
}
}

Answer 2

Your code has lot of errors. Return type is not defined for function. Where is i variable come from in tobinary() function? Solve it proper.

Answer 3

import java.util.Scanner;
public class converter{

public static int toBinary(){
int x = 0;
return x;
}
public static int toBinary (int x){
String binary ="";
while(x>0){
binary = x%2 + binary;
x /=2;
}

}
}
//your code goes here

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
System.out.print(Converter.toBinary(x));
}
}

Answer 4

Is it right?

Answer 5

eg suppose the method returns a String, then

String method() { //return type before method name
String s = "abc";
return s; //return value of type declared above
}