I think there is something wrong with this code, I don’t know what it is though

Question

def fun(x):
if x % 2 == 0:
return 1
else:
return

print(fun(fun(2)) + 1)

Answer 1

Jenkins
Were you trying to do this?

def fun(x):
return x%2 ==0

print(fun(fun(2))+1)

Answer 2

The problem is that if number is odd, your function returns nothing (None type) which is a problem, as later you are trying to add "None" to 1, which python obviously can't do.

Answer 3

Maybe you wanted print(fun(fun(2)+1)) #1

Answer 4

Rik Wittkopp 👍😉