CPP code project . How did you solve #ticket_office project on C++ .

Question

I used nested if , is there a better way to do it ?

C++ 35 code project . Ticket office

https://code.sololearn.com/coyTWPukjJtO/?ref=app

Answer 1

Elias ,

instead of using the if ... construct to find the minimum number, you can sort the number array and then take index[0] to pick the minimum nunber.

don't forget to include: #include <bits/stdc++.h>

here a link how it could be done:
https://www.geeksforgeeks.org/sort-c-stl/

Answer 2

Elias

Assign first value of the array in a variable as a min value then compare this min value with next value until you don't get min value.

So you can do like this:

int minage = ages[0];

Now compare this with next values inside for loop.

for(int i = 0; i < 5; i++) {
if (minage > ages[i]) {
minage = ages[i];
}
}

cout << 50 - (50.0 * minage / 100);

---------Here is another way without loop-------

int n = sizeof (ages) / sizeof(ages[0]);

int &min = *min_element(ages, ages + n);

cout << 50 - 50 * (min / 100.00);

You need to import this header file for this solution:

#include <bits/stdc++.h>

Answer 3

Thank u so much A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ and Lothar . It's a lot of help

Answer 4

Elias [101]

I am sure you did some mistakes.

Try this and tell if there is any issue

int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}

int minage = ages[0];

for(int i = 0; i < 5; i++) {
if (minage > ages[i]) {
minage = ages[i];
}
}

cout << 50 - (50.0 * minage / 100);

Answer 5

A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟
Yes you are right
Works fine now👍 thank u again
u got ur self a follower hh

Answer 6

Elias

You have written Hard Code if else conditions if there are more than 10 inputs then what?

Answer 7

A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ the first method it runs perfect and the output is also correct but there is a warning massage "ages[0] is used uninitialized in this function"

Answer 8

A͢J - S͟o͟l͟o͟H͟e͟l͟p͟e͟r͟ you are right that's why I am asking for a better solution

Maybe we could use while loop for the nested if🤔.