Please help. Why do the arguments passed in the function automatically convert to a tuple?

Question

def fun(*val):
print(type(val))

one = [1,2,3,4,5]
number = 400
fun(one,number)

Answer 1

Because the parameter "val" has the '*' in front of it in the function definition.

it's usually set up like:

def func(*args, **kwargs):
...

*args being an arbitruary amount of arguments
*kwargs being the same for dictionary values

Answer 2

Yes and no, there are lots of ways it can be set up. And its a tuple because tuples can't be changed and that just makes logical sense. You put a bunch of values into a function so there's no way to change what you've already fed the function, hence, the tuple.

Answer 3

Slick

Thank you bro

Answer 4

Slick

So ‘*’ automatically converts it to a tuple?

Answer 5

* in front of a parameter name converts all subsequent values given to an iterable which can then be looped through. It's a tuple because the arguments are given once and can't be changed. No sense in changing them

Answer 6

Slick
Sorry, just to clarify the answer , so * in front of a parameter always converts values to a tuple? Yes? It can’t never be a str, list or anything else, always a tuple?