include <stdio.h> int main() { int b=7,a; a=b++ + ++b+b++ ; printf ("%d\n",a); return 0; }

Question

Explanation please

Answer 1

#include <stdio.h>
int main()
{
int b = 7, a;
a = b++;
printf("%d\n",a);

a += ++b;
printf("%d\n",a);

a += b++;
printf("%d\n", a);
return 0;

}

Answer 2

a=b++ + ++b+b++;
1)a=((b++)+(++b))+(b++);
2)++b = 8
3)b++ = 8
4)b++ = 9
5)a=8+8+9
6)a=25 b=10

Answer 3

I am unable to explain via chat therefore i have shared code explaination, if you know use of ++b or b++ then you will understand it.

if you dont know about it then do some research

Answer 4

Please always tag the language you're asking about.
https://code.sololearn.com/W3uiji9X28C1/?ref=app

Answer 5

It produces garbage value at the result due to the variable A value
is not defined.

Just check this link for your understanding about the unary operators in c.
https://www.quora.com/What-is-a-a-b-b-if-a-is-4-and-b-is-5/answer/Raghul-A-25?ch=10&oid=300627272&share=8d139834&srid=hqEi0&target_type=answer

Answer 6

25