How its sum becomes 6? Can someone explain?

Question

int array[2][2]={0,1,2,3};
int i=0,sum=0;
for(i=0;i<4;i++)
{
int x,y;
x=i%2;
if (x){
y=0;
}
else{
y=1;
}
sum+=array[x][y];
}
printf("%d", sum);

Answer 1

Bikesh,
Add this line before adding array[x][y] to <sum>. It might just give you an dea.

printf("adding array[%d][%d] (%d) to <sum> -> %d\n", x, y, array[x][y], sum + array[x][y]);

Answer 2

I am getting 0 how you are getting 6?

https://code.sololearn.com/cB3Qr187t1lK/?ref=app

Answer 3

Ohh sorry! I just forget to put the values in curly brackets.
Now it's corrected. Try once again.