+ 2

why does this code print 6? Please tell me in deep please.

https://code.sololearn.com/cLsuZfktuH4Q/?ref=app

3rd Apr 2017, 10:27 AM
Dhananjay Panage
Dhananjay Panage - avatar
2 Réponses
+ 11
First loop: x is 0, i is 1 (x + i) is 1, assigned to x Second loop: x is 1, i is 2 (x + i) is 3, assigned to x Third loop: x is 3, i is 3 (x + i) is 6, assigned to x Outputs x: outputs 6
3rd Apr 2017, 11:00 AM
Hatsy Rei
Hatsy Rei - avatar
+ 1
You enter the for-loop with x=0, i=1. x get reassigned: x = 0 + 1, i++ lets i become i+1 = 2. As 2<4, you stay in the loop with x=1, i=2. x get reassigned: x = 1 + 2 = 3. i++ lets i become i+1 = 2. As 3<4, you stay in the loop with x=3, i=3. x get reassigned: x = 3 + 3 = 6. i++ lets i become i+1 = 4. Now 4<4 is false and the loop exits with x being 6. You print x, which has value 6.
3rd Apr 2017, 10:55 AM
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