Can anyone help on how to get the employee with the highest net pay using Java?

Question

import java.util.*;

public class LabExercise {

public static void main (String[] args) {

double grossPay;
int hoursWorked;
int ratePerHour;
double totalDeduction;
double amountTax;
double amountSSS;
double amountPhilhealth;
double netPay;
String nameOfEmployee;
int numberOfEmployees;
int initialNumberOfEmployees = 1;

Scanner input = new Scanner (System.in);
System.out.print("Enter number of employees: ");
numberOfEmployees = input.nextInt();

while (initialNumberOfEmployees <= numberOfEmployees) {

System.out.println("\nEmployee No. " + initialNumberOfEmployees);
input.nextLine();

System.out.print("Enter Employee Name: ");
nameOfEmployee = input.nextLine();

System.out.print("Enter Hours Worked: ");
hoursWorked = input.nextInt();

System.out.print("Enter Rate per Hour: ");
ratePerHour = input.nextInt();

grossPay = hoursWorked * ratePerHour;
System.out.println("Gross Pay: " + grossPay);

amountTax = grossPay * 0.12;
System.out.println("Tax: " + amountTax);

amountSSS = grossPay * 0.05;
System.out.println("SSS: " + amountSSS);

amountPhilhealth = grossPay * 0.02;
System.out.println("Philhealth: " + amountPhilhealth);

totalDeduction = amountTax + amountSSS + amountPhilhealth;
System.out.println("Total Deduction: " + totalDeduction);

System.out.println("Employee Name: " + nameOfEmployee);

netPay = grossPay - totalDeduction;
System.out.println("Net Pay: " + netPay);

initialNumberOfEmployees++;
}

input.close();
}
}

Answer 1

Store the net pays for all the employees in a List.

Then use the method Collections.max() on netPayList to find the highest net pay.

Answer 2

Can it also display the name of the employee with the highest net pay?

Answer 3

No, for that a Map would be better. Since you can have Employee name as key and netPay as value. Then you can just find the key associate with max value.
----

Why don't you finish the java course?
The last project "Bowling game" is similar to what you want to achieve.
i.e. Find the key with max value.