explain a[0].length in 2nd loop please tell me how its working

Question

int a[][] = { { 1, 3, 4 }, { 2, 3, 6 }, { 7, 6, 5 } };
int sum = 0;
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[0].length; j++) {
if (a[i][j] % 2 == 0)
break;
sum += a[i][j];
}
}
System.out.println("sum = " + sum);
}
}

Answer 1

From the program it looks like you are trying to add the odd numbers in the given 2D array.
int arr[][] = {{1,3,4},{2,3,6},{7,6,5}}
Here arr[0] = {1,3,4}
And arr[0].length = 3

For the program to work properly you should use arr[i].length because you might have inner arrays with different lengths.

Answer 2

yes I got it answer of my question

a[0].length simply means Zeroth indexs element length

a = { 1, 3, 4 }, { 2, 3, 6 }, { 7, 6, 5 }

So at zeroth index there are 3 elements 1,,3,4 so length is 3

Or

a.length is the number of rows. a[0].length is the number of columns.