Boolean logic age groups python

Question

age = int(input())

if age >= 0 and <= 11:

print("Child")

elif age >= 12 and <= 17:

print("Teen")

elif age >= 18 and <= 64:

print("Adult")

else

print("senior")

I watched for the solution but everyone write the same and i still got syntax error.
I need only the hint why this code recieves the message 'invalid syntax error' , line 3.

Answer 1

Sasha Krömtz if you still doesn't know Jayakrishna🇮🇳 tried to say you need a variable before <= 11: becouse <=11 doesn't know whith what variable to compare it.

Answer 2

Invalid syntax in

if age >= 0 and <= 11:
#hope you find correct way

And
: missing after last else.

Answer 3

Maybe becouse you forgot to ad : after else I think it should help (python hasn't got very good error messanges)

Answer 4

I add it but still the same. I have this solution silce over a day, and like every solution i was trying to find. Looks like mine, but i still have this 'invalid syntax error'. And bro really, i cant understand this.

Answer 5

Sasha Krömtz You want clue and it is :

if age >= 0 and <= 11: invalid syntax!
What is 2 condition here? Incomplete one..

Answer 6

Jayakrishna🇮🇳 my english isnt the best, but i think you writing the except code iam writing. And i already tried different versions, and i dont know what you trynna say to me.

Answer 7

You can write in your own language..
I use google translate..
I said where is mistake. You have find correct way by revision the lesson.. Sasha Krömtz Do you want solution..? better, you to try again

Answer 8

Omg guys i was so blind for this. Ahhahaha

Answer 9

2 ISSUES:
1) You need to add "age" for each check you do:
2) The last ELSE is missing a colon.
The correct version would be as below:

age = int(input())

if age >= 0 and age <= 11:
print("Child")

elif age >= 12 and age <= 17:
print("Teen")

elif age >= 18 and age <= 64:
print("Adult")

else:
print("senior")