Unexpected dereferencing of char array?

Question

When I try to dereference a char array in printf() standard function using the "%c" format specifier for char it delivers the first character. Has it anything to do with the fact that arrays of C types are kind of pointers or the like? How can I dereference a non-pointer variable? If it dereferences, so can I consider that a pointer also?

This is the code:

#include <stdio.h>

int main (void) {
char str [50] = "Hello, World!";
printf ("%c", *str );
}

Output: H

Conversely, if you code a char pointer, you can assign it a string and use "%s" format specifier to the char pointer to print the "char array".

This is an example code:

#include <sdtio.h>

int main (void) {
char *str = "Hello, World!";
printf ("%s", str );
}

Output: Hello, World!

Answer 1

You can refer to these links for the query...
https://stackoverflow.com/questions/10186765/what-is-the-difference-between-char-array-and-char-pointer-in-c
https://www.geeksforgeeks.org/whats-difference-between-char-s-and-char-s-in-c/

Answer 2

Thanks ROOKIE for the tip!