Java 16.2 Need help

Question

I need help with Java 16.2. My Code:

import java.util.Scanner;

public class Main
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int number = scanner.nextInt();
int fact = number;
//your code goes here
while (number > 1){
fact = number * number--;
number = number--;
}
System.out.println(fact);
}
}

Answer 1

Inside the loop needs to be:

fact = fact * number; // update fact
number--; // decrease number once

Answer 2

number-- decreases it by 1, number-- again decreases it once more by 1

Answer 3

Only increase number once per loop iteration

Answer 4

Oh yes thanks i mean fact = fact*number but yet it doesnt give any output

Answer 5

Can you please put your updated code in a script on sololearn playground and link it?

Answer 6

number-- works inplace,

so

number--;

or

number = number - 1;

Answer 7

Oh yes yet it worked thank you very much

Answer 8

But what helps me that? Because I want the number to always be lowered by one so that the program stops at the end.

Answer 9

and I think it should be fact = fact*number in the loop

Answer 10

in the given code it's int fact = 1; isn't it? Leave it like that...

Answer 11

Yet the output is: Execution Timed out!

Answer 12

https://code.sololearn.com/cq56bXp323p6/?ref=app

Answer 13

Its still: Execution Timed out

Answer 14

input fact = 1
then in your code
fact = fact*number;
number--;