Random Math problem generator

Question

Hello I need help. I am trying to input the function so that should take "+,-,*, or /" as an choice in order to then input a random math problem to solve based on the symbol the user picked however whenever i input one of these symbols it will mark it as wrong or will say it isnt one of the symbols listed above, how can i make it so that the quote " cout << "SORRY, PLEASE ONLY ENTER A SYMBOL LISTED ABOVE!";" doesnt pop up when I actually input a symbol listed above?

//C++ Program FINAL PROJECT
//Gabriel Reyes, February 5, 2022 CIS-5

#include<iostream>
#include<cmath>
using namespace std;

int main()

{

char sym_choice; //Symbol Choice
int one, two;
cout << "\tHello, please Select A symbol to\n";
cout << "\tsolve a random math problem between\n";
cout << "\t(+,-,*,/)\n\n";
cout << "\tENTER YOUR CHOICE: ";
cin >> sym_choice;

if (sym_choice != '+', '-', '*', '/')
{
cout << "SORRY, PLEASE ONLY ENTER A SYMBOL LISTED ABOVE!";
}

int answer = 0;
bool CORRECT = false;
one = rand() % 500 + 1;
two = rand() % 500 + 1;
std::cout << "What is " << one << " " << sym_choice << " " << two << "? ";

switch (sym_choice) {
case '+':
if (answer == one + two) CORRECT = true;
break;

case '-':
if (answer == one - two) CORRECT = true;
break;

case '*':
if (answer == one * two) CORRECT = true;
break;

case '/':
if (answer == one / two) CORRECT = true;
break;
}
if (CORRECT == true)
{
cout << "Nice job!" << endl;
}

return 0;
}

Answer 1

Inside the if block that checks your symbol, add a line
👉return 1;👈

EDIT: Also change the final print to be
👉cout << answer << "\nNice job!" << endl;👈

https://code.sololearn.com/c2wl012Yn46D/?ref=app

EDIT 2: My version as linked above. Requires the rand function to be seeded. I'll investigate how to do that in C++. it needs:

#include<ctime> // in the headers
srand (time(NULL)); //in main()

Answer 2

This is invalid syntax for the conditional expression that you intended:

if (sym_choice != '+', '-', '*', '/')

Try something like this:

if ((int)string("+-*/").find(sym_choice)<0)

Answer 3

Looks like you forgot to read <answer> value in. I see <answer> was defined as 0, and a prompt for <answer>, but I don't see where <answer> was read in (except you've made some changes in the actual code).

Answer 4

Thank you! but now if I try to input a symbol other than the ones listed below it will proceed with the problem anyways! e.g.: 20 ! 410, 60 ? 200, only after would it output " "SORRY, PLEASE ONLY ENTER A SYMBOL LISTED ABOVE!";"