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Find and replace a word in a string and count how many replacements occurred? Whatâs the wrong in my code or any solution?
text = "Amy has 128 dollars, while David has 54 dollars. Amy is going to the zoo. David watches soccer." f = input() r = input() c =0 while(text.find(f))!= -1: text = text.replace(f,r) for w in text.split(): if w == r: c = c +1 print(c) print(text)
2 RĂ©ponses
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Md.Delwar Hossain
First count then replace.
also in case of text.split() will not work because in this case "dollars," or "dollars." would be considered as a string means comma and dot will also be join with string so
'dollars' == 'dollars,' # would be false
So
Simply you can use count function and replace function directly without loop
print (text.count(f))
print (text.replace(f, r))
0
Thanks. My problem is I always think complex way where there is a simple solution available.