i want the root value of these numbers

Question

#include<stdio.h>
#include<math.h>

int main()
{

double a;
double b;
double c;

printf("Enter the value for square root\n");

scanf("%lf", a);
printf("%lf\n", &a);

scanf("%lf", &b);
printf("%lf\n", b);

c = sqrt(a*a, b*b);

printf("The square root is %lf", c);

return 0;

}

Answer 1

c=math sqrt (a*a)

Answer 2

You're using address operator(&) in printf() instead of scanf() for variable a.
sqrt function takes a single argument only.
c = sqrt(a*a) or c = sqrt(b*b)

Btw, square root of x*x is always x.

Answer 3

It looks like you want to find the hypotenuse of a triangle. There is a math function for that called hypot().

Your pointers are mishandled in scanf and printf. Here is the corrected code:

#include<stdio.h>
#include<math.h>

int main()
{

double a;
double b;
double c;

printf("Enter the short sides of the right triangle\n");

scanf("%lf", &a); //<-- added ref
printf("%lf\n", a); //<--removed ref

scanf("%lf", &b);
printf("%lf\n", b);

c = hypot(a, b); //was sqrt(a*a, b*b);

printf("The hypotenuse is %lf", c);

return 0;

}