Explanation for the code(Python)

Question

I've come across this code in Sololearn " challenge" but failed to grasp the essence of it.
Can someone help me with it?

y=[x if x==1 else x*2 for x in ["1","2"]][0]
print (y)

The output is "11",but how?

Answer 1

In short, "1"*2 = "11". It is Python string multiplication.

Note that x==1 is false both times.
"1"==1 (false)
"2"==1 (false)

So it uses x*2 on both elements.

After list comprehension is done, it makes
["11", "22"]

And y= ["11", "22"][0] = "11"
print(y)

Output:
"11"

Answer 2

Brian , Avitus ,

sorry, you are right. oops - i must have been blind!

Answer 3

Brian Thanks very much!!!

Answer 4

Now we know Lothar is a human like us 😄!

Answer 5

Lothar the presumption of a typo is unnecessary. It works as it was originally presented. Try removing the [0] from the end. Then y is assigned the intermediate list ["11", "22"], and then that is what gets printed.