Hi, Can you give me a tip about how i print counted letters in input's order? The code in this post print them randomly

Question

text = input()
mydict = {}

letters = [a for a in text]

mydict = dict((i, letters.count(i)) for i in set(letters))

print(mydict)

Answer 1

Arif Şhn
The text variable will produce a string which may be iterated upon directly.

You won't need to worry about duplicate items in the dict, because each key is unique.

text = input()

mydict = dict((i, text.count(i)) for i in text)

print(mydict)

Answer 2

Arif Şhn

Use list instead of set because set will replace previous value with next value so suppose input is "anant" so set will give ['n', 'a', 't']

Answer 3

Thank you both🙏

Answer 4

A͢J Isn't the order of elements random every time with a set? I don't understand.

Answer 5

Korkunç el Gato you are right! Even if the text provided by user has unique characters (not repeating chars as set() will remove them), it will print them randomly.

I am not sure how it works though.

Answer 6

Korkunç el Gato i am not sure if it is always the case but doing set(a) will return a set with item sorted (tried with numbers). Therefore, maybe it's not random.

Note: Here, a is list containing duplicate random chars.

Answer 7

Thanks for removing the confusion Sandeep.