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Need solution
What is the output? x=0 while x<5: x=x+2 print(x) How the answere is 6? Prblem:2 x=0 a=[ ] while x <=3: x*=2 a.append(x) print(a) How the answere is infinite loop? Explain please!
11 Réponses
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Problem 1
X= 0, in first loop x= x+2 = 2, second 2+2;= 4, and third 4+2= 6, then x>5 so while loop breaks. And x is printed.
Problem 2
Your while loop is an infinite loop because perhaps you forgot to increase x, in the loop.
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No, you are misunderstanding while loop with for loop perhaps or idk. It is straight x= 0+2, 2+2,4+2
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Problem 1:
The while loop does 3 iterations before exiting, each time adding 2 to x. So 2 + 2 + 2 = 6. Right before the 4th iteration, x < 5 is no longer true, so the loop exits.
Problem 2:
It is an infinite loop because x is always 0, which means x <= 3 is always true. This is because x *= 2 computes 0 * 2 = 0.
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But while x<5 mean x=0,1,2,3,4
Why just 2+2+2?
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While loop does not increase the x automatically, it is increasing by 2 because it is in the code 'x = x+2'
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x increases by 2 each time because of `x = x + 2`. So the x values are not 0, 1, 2, 3.. but 0, 2, 4, 6
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prloblem 1
If i share what i think about that is
X=0+2, x=2+2
X=1+2, x=3+2
X=2+3, x=5+2
Like that???
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For problem 1,
X = 4+2 = 6 ( because our condition is x<5 so, lastly we have to consider x = 6 as our final answer.
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Hello can anyone please tell me how python helpful?
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Good luck Bushra Saleem