Help explain the output.

Question

#include<stdio.h>
void main()
{
int i,n,a[100];
printf("-----------------------------------------\n");
printf("Input the number of elements to store in the array : ");
scanf("%d", &n);

printf("Input %d number of elements in the array :\n",n);
for(i=0;i<n;i++)
{
printf("element - %d :", i);
scanf("%d",&a[i]);
}
printf("\nThe values store into the araay are : \n");
for(i=0;i<n;i++)
{
printf("%5d",a[i]);
}
printf("\n\nThe values are : \n");
for(i=n-1;i>=0;i--)
{
printf("%5d",a[i]);
}
printf("\n\n");
}

Answer 1

The last loop starts from index <n> - 1 for example, if <n> was 5, the loop begins from index 4 (5 - 1)

The loop repeats while the loop counter <i> is greater than or equals to zero. So when <n> was 5, the loop will repeat in sequence 4, 3, 2, 1, 0

Basically the loop iterates the array in backwards and displays the value of element at index <i>

Answer 2

What exactly do you not understand?

Answer 3

Can you explain how the last for loop works?