How copying of lists work in Python?

Question

>>>a=[2,3,4]
>>>b=a
>>> # now a and b, both refers same memory address
>>># check memory addresses with print(hex(id(a))) and print(hex(id(b)))
>>>del a
>>>b
[2,3,4]

So where does this variable [2,3,4] actually stored? Explain, please.

Answer 1

The list is stored until at least one variable points to it. The del command just destroys one of the pointers. The list itself is stored in yet another place - try to print hex(id([2,3,4])) along with those of a and b, to see that.

Answer 2

notable point of list copying is list by default follows shallow copy.

here is code you can check and understand.

https://code.sololearn.com/cDssM174GLKf/?ref=app

Answer 3

Actually python has automatic memory management.

=> Automatic memory management: If the values of python variables are same then it allocates a single memory block.

so if you have delete one obj , other is still pointing to same memory location.