+ 2

What mistake have on this code ?

text = input() l=list(text) a=-1 b=1 while len(l)>b: a+=b b+=1 k=(l[a]:l.count(l[a]))*len(l) di={k} print(di)

2nd Jan 2023, 12:08 PM
Imran Shakil
Imran Shakil - avatar
11 Réponses
+ 1
Hi again, Imran Shakil ! How do you mean? Dictionaries are unordered collections. The represention of a dictionary vary with Python version. Later versions of Python (+3.6) makes it possible to affect the representaion. That is what I do with the sorted() function. The dictionaries content is still the same. You can take away the the sorted function, it just makes the dictionary representation easier to read. s = input() d = {c: s.count(c) for c in set(s)} print(d) https://code.sololearn.com/c7Q9bLORrURB/?ref=app
2nd Jan 2023, 3:28 PM
Per Bratthammar
Per Bratthammar - avatar
+ 6
here is a corrected version of the code https://code.sololearn.com/c0v3maaOQ8ww/?ref=app
2nd Jan 2023, 1:48 PM
Sadaam Linux
Sadaam Linux - avatar
+ 1
Hello Imran Shakil, It appears that you have accidentally created two similar questions. To avoid confusion, it would be best if you could remove one of these questions. Here is the link to the other question for reference: https://www.sololearn.com/Discuss/3178684/?ref=app Thank you :)
2nd Jan 2023, 1:29 PM
Jaydeep Khatri
Jaydeep Khatri - avatar
+ 1
Per Bratthammar thank you so much...I dont how I should thank you. ... I hav solved this problem by your help.
2nd Jan 2023, 3:37 PM
Imran Shakil
Imran Shakil - avatar
0
What is the correct form of this code? text = input() l=list(text) a=-1 b=1 while len(l)>b: a+=b b+=1 k=(l[a]:l.count(l[a]))*len(l) di={k} print(di)
2nd Jan 2023, 12:09 PM
Imran Shakil
Imran Shakil - avatar
0
Hi, Imran Shakil ! What are you trying to do? Are you trying to create k as a dictionary, or do you try to slice the list l?
2nd Jan 2023, 12:33 PM
Per Bratthammar
Per Bratthammar - avatar
0
k variable is wrong, because: from while loop, if we type "hello", for instance, the value of a = 9, and value of b = 5 afterwards. l variable doesn't have the value which has an index of 9 — stated in the "k" variable — therefore error. **count(I[a])** — also seems to be wrong due to the same reason, as mentioned above.
2nd Jan 2023, 12:37 PM
Lamron
Lamron - avatar
0
What is the solution of this? :- Given a string as input, you need to output how many times each letter appears in the string. You decide to store the data in a dictionary, with the letters as the keys, and the corresponding counts as the values. Create a program to take a string as input and output a dictionary, which represents the letter count. Sample Input hello Sample Output {'h': 1, 'e': 1, 'l': 2, 'o': 1}
2nd Jan 2023, 2:31 PM
Imran Shakil
Imran Shakil - avatar
0
Hi Per Bratthammar I want to solve this: - Given a string as input, you need to output how many times each letter appears in the string. You decide to store the data in a dictionary, with the letters as the keys, and the corresponding counts as the values. Create a program to take a string as input and output a dictionary, which represents the letter count. Sample Input hello Sample Output {'h': 1, 'e': 1, 'l': 2, 'o': 1}
2nd Jan 2023, 2:36 PM
Imran Shakil
Imran Shakil - avatar
0
# Hi, Imran Shakil ! # You can take a look at this: s = input() or "Jack and Jill" d = {c: s.count(c) for c in sorted(set(s))} print(f"{d = }")
2nd Jan 2023, 2:49 PM
Per Bratthammar
Per Bratthammar - avatar
0
Per Bratthammar Thank you so much. But unfortunetly this code is unable to return expected output.
2nd Jan 2023, 3:03 PM
Imran Shakil
Imran Shakil - avatar