Friends can you please tell me the exact way of how the assigned value and output aren't equal?

Question

https://code.sololearn.com/c7rKvl02kdZH/?ref=app

Answer 1

short type takes only 2 bytes.
Unsigned values can't hold negative values. So you can only store values between 0 to 65535.

So your int value -3755768, will be converted to unsigned short int value to store in compatible type....
Generally, 2's compliment form of number is the converted value..
So the -3755768 number 2's compliment form is 45320 in 2 bytes range. overflown bits are ignored..

Answer 2

Keerthana.S

What are you trying to do?

Your attempting to assign a value of ‘minus 3755768’ to an unsigned short.

Unsigned (clue in the name) doesn’t include the sign bit.

Also the range for a unsigned short is 0 to 65,535, much less than needed.

Implicit type conversion happening, then your print format specifiers are for an unsigned and signed int 🤔

To store -3755768 correctly you would want to be using a signed int.

The correct format specifier with print function would be %d.

The assigned value and output value differ because of the conversion - if correctly assigned types the output is the same:

int a = -3755768;
printf("%d", a);

Answer 3

if your are on js its object != value ...i hope this helps