How the second for loop works in below program

Question

public class Program
{
public static void main(String[] args) {

int numbers[] = { 1,2,3,4,1};

for( int i:numbers)
numbers[i] = 0 ;
for( int i:numbers)
System.out.println(i) ;
}
}

Answer 1

1) numbers[0] = 1
but numbers[0] = 0
sout(0)
2)numbers[1]=2
but numbers[i=1]= 0
sout(0)
3)numbers[2]=3
but numbers[i=2]=3
sout(3)
4)numbers[3]=4
but numbers[i=3]=0
sout(0)
5)numbers[4]=1
but numbers[i=4]=1
sout(1)

I hope you understand

Answer 2

Pay attention to the first loop: The element at i is replaced with 0. Again, i is the element, not the index.

Answer 3

The second loop works just like the first loop.
For each i in numbers, i is printed.

Answer 4

how? can u elaborate the answer ? 00301 why this is answer

Answer 5

For each i in numbers, i is printed. i is the element in the array.

Answer 6

why answer is 00301

Answer 7

answer should be 00000

Answer 8

not understood !!! plz help me

Answer 9

if you want 0000
you should NOT use
for(int i:numbers)
this will give you values, not indices.
you should use
for(int i=0;i<numbers.length;++i)
then you can use numbers[i]=0;
in a way that makes more sense.

public class Program
{
public static void main(String[] args) {

int numbers[] = { 1,2,3,4,1};

for(int i=0;i<numbers.length;++i)
numbers[i] = 0 ;
for( int i:numbers)
System.out.print(i) ;
}
}

Answer 10

Inside loops always completes before returning back to the outer loop for example

Loop1(2times)
Loop2(3times)

Loop1 (outside loop)
Looo2
Looo2
Looo2
Loop1 (back to outside loop)
Loop2
Loop2
Loop2
Finished