Why else did not work

Question

#جواب به توان n عدد مختلط (i)
h = input()
d = h % 4
if d == 0 :
print ("1")
elif d == 1 :
print ("i")
elif d == 2 :
print ("-1")
elif d == 3 :
print ("-i")
else :
print ("undefined")

Answer 1

When you input a word of character then int(h) will raise error.

If you put any valid number then d value can be 0,1,2,3 only. No other values possible so else part is no use..

You may trying to exception handling when input is not valid number?
Then try :

h = input()
try :
d = int(h) % 4
if d == 0 :
print ("1")
elif d == 1 :
print ("i")
elif d == 2 :
print ("-1")
elif d == 3 :
print ("-i")
except :
print ("undefined")

Answer 2

AmIraN gh ,

we still lack a useful task description.

> can you please tell us what your code should achieve?

Answer 3

input() accept as string format. Convert to needed type. Otherwise h%4 is error.

h = int( input() )

Answer 4

You only need to handle any letter before entering the if else statments

try:
h = int(input())
except ValueError:
print("Undefined")

d = h % 4
if d == 0 :
print ("1")
elif d == 1 :
print ("i")
elif d == 2 :
print ("-1")
elif d == 3 :
print ("-i")

Answer 5

Jayakrishna 🇮🇳 and Mohamed Youssef Belloui I'm sorry what about this coad
Why else did not work about words and sentences

h = input()
d = int(h) % 4
if d == 0 :
print ("1")
elif d == 1 :
print ("i")
elif d == 2 :
print ("-1")
elif d == 3 :
print ("-i")
else :
print ("undefined")

Answer 6

Jayakrishna 🇮🇳 thank you so much

Answer 7

Lothar In math there is a case about complex numbers.
So I create this coad to find the answer of complex numbers power

Answer 8

I want to print Undefined when the user prints word in the input