Pattern printing in cpp

Question

I have to print a pattern like this
*
##
***
####
*****
But the hash symbol wasn't displayed in the way I expected what's the problem with my code anyone help me!?

#include <iostream>
using namespace std;

int main() {

int rows;

cin >> rows;

for(int i = 1; i <= rows; ++i) {
if(i%2==0)
{
cout<<"#";
}
else{

for(int j = 1; j <= i; ++j) {
cout << "* ";
}
}
cout << "\n";
}
return 0;
}

Answer 1

maha Lakshmi

Using ternary operator

#include <iostream>
using namespace std;

int main() {
int rows;

cin >> rows;

for(int i = 1; i <= rows; ++i) {
for(int j = 1; j <= i; ++j)
cout << ((i % 2 == 1) ? "*" : "#");

cout << "\n";
}

return 0;
}

Answer 2

// you need similar to * loop for #

#include <iostream>
using namespace std;

int main() {
int rows;
cin >> rows;

for(int i = 1; i <= rows; ++i) {
if(i%2==0)
{
for(int j = 1; j <= i; ++j) {
cout << "# ";
}
}
else{

for(int j = 1; j <= i; ++j) {
cout << "* ";
}
}
cout << "\n";
}
return 0;
}

Answer 3

You forgot the for loop for the #.

Answer 4

U can reduce your code remove both inside loops and write only once like this

// you need similar to * loop for #

#include <iostream>
using namespace std;

int main() {
int rows;
cin >> rows;

for(int i = 1; i <= rows; ++i) {
for(int j = 1; j <= i; ++j) {
if(i%2==0)
{
cout << "# ";
}
else{

cout<< "* ";
}
}
cout << "\n";
}
return 0;
}