Search engine challenge - python beginner

Question

I don't understand the solution for the easy search engine. It was something like:
If [string] in [string with multiple words]:
Print("found")
Else:
Print("not found")

In which lesson did we learn that we can look for a part of a string using the if-statement? I couldn't find it. I do understand the logic behind the loop, but I don't know when I learned it.

Answer 1

Simba Estreich ,

the *search engine* exercise is the last one in the tutorial. it requires the *in* operator.

> this is explained in the *python for beginners* tutorial in the chapter *lists*

> the lesson 32.1 *list operations* demonstrates:

words = ["spam", "egg", "spam", "sausage"]
print("spam" in words)
print("egg" in words)
print("tomato" in words)

and it also says: The *in* operator is also used to determine whether or not a *string* is a *substring* of another string.

Answer 2

#Aim of the program is to check for a word in a given sentence and print found if it's present
So the solution will be
text = input()
word = input()
def search(text,word):
if word in text:
return("Word found")
else:
return("Word not found")
print(search(text,word))

Answer 3

Lothar,
Thank you so much! I knew I overlooked something!

Answer 4

Please go through introduction of python one more time than you will
Find logic behind the loop
An about if statement

Answer 5

You have to understand the aim
Then you can solve it
I think you did not understand was the aim of code

Answer 6

If I am wrong please correct me

Answer 7

Thanks herobrine for your answers. I did understand the goal and I tried with big loops. But the solution (in my post) surprised me, because it was so easy. I expected a "bigger" solution, as it was the final project for the beginner course. But because it was such an easy solution, I wondered where in the course they taught that you can search for a word in a string, only using a if-loop.