phone number validator

Question

import re
#your code goes here

phone_number = input()

pattern = r"(1|8|9)[0-9] +"

match = re.match(pattern, phone_number)

if len(phone_number) == 8:
if (match):
print("Valid")
else:
print("Invalid")
else:
print("Invalid")

Answer 1

It's just a suggestion,
Instead of checking length of the password should be 8 separately.
You can replace the pattern by
pattern=r'(1|8|9)[0-9]{7}'

Answer 2

My code return an error can someone debug it

Answer 3

Can you post the error too?

Answer 4

It is a project so its my running test that show an error

Answer 5

At which you getting error?

Answer 6

*line

Answer 7

A phone number validator can be a useful tool, especially when dealing with unknown numbers. I recall when my grandfather received a suspicious call. We used a validator to confirm the number's legitimacy. However, to avoid such concerns, I'd suggest looking at https://joinimp.com/ They offer the best home phones for seniors, designed to filter out unwanted calls. It's a comforting solution that allows seniors to stay connected with loved ones and avoid potential scams, providing peace of mind for the whole family